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A foot ball bladder contains equimolar proportion of $H_{2}$ and $O_{2}$ Find the composition by moles $(H_{2} : O_{2})$ of the mixture effusing out of punctured foot ball

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2 : 3

4 : 1

1 : 4

5 : 4

answer is C.

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Detailed Solution

${(\frac{n_{1}}{n_{2}})}_{\begin{array}{l} e f f u s e d \\ o u t \end{array}} = {(\frac{n_{1}}{n_{2}})}_{i n s i d e} \sqrt{\frac{M_{2}}{M_{1}}}$

${(\frac{n_{1}}{n_{2}})}_{\begin{array}{l} e f f u s e d \\ o u t \end{array}} = 1 \times \sqrt{\frac{32}{2}} = \frac{4}{1}$

$(n_{H_{2}} : n_{O_{2}}) = 4 : 1$

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