(A) For the reduction of esters into alcohols, Ni/H₂ is preferred than LiAlH₄.
(R) LiAlH₄ is more expensive than Ni/H₂

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Both ‘A’ and ‘R’ are true and ‘R’ is the correct explanation of ‘A’.

‘A’ is false and ‘R’ is false

Both ‘A’ and ‘R’ are true and ‘R’ is not the correct explanation of ‘A’

‘A’ is true and ‘R’ is false

answer is A.

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Detailed Solution

$Esters \overset{{LiAlH}_{4}}{\to} Alcohols$

Carboxylic acids, esters and amides are less reactive, and thus, cannot be reduced by catalytic hydrogenation, except under extreme conditions.

This means that LiAlH₄ is an expensive reducing agent.

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