A force 11.0 N acts on body of mass 100 kg. As a result the body covers 1000 cm in 4 seconds moving along straight line. The initial velocity

$\text{F}=\text{ma}$

$\text{a}=\frac{\text{F}}{\text{m}}$

$\text{a}=\frac{11}{100}=0.11$

$\Rightarrow \text{from 2nd eqn of motion}$

$\text{S}=\text{ut+}\frac{1}{2}{\text{at}}^{\text{2}}$

$1000\times {10}^{-2}=\text{u}\times 4+\frac{1}{2}\times 0.11\times 4\times 4$

$10=4\text{u}+0.88$

$10-0.88=4\text{u}$

$4\text{u}=9.12$

$\text{u}=\frac{9.12}{4}\Rightarrow 2.28\text{m/s}$