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Q.

A force acting on a particle of mass 200 g displaces it through 400 cm in 2 seconds. If the initial velocity of the particle is zero, then the magnitude of the force is

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a

40 N

b

400 N

c

4 N

d

0.4 N

answer is A.

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Detailed Solution

Question Image

$m = 200 g = 200 \times 10^{- 3} kg = 0 .2 kg$

$s = 400 cm = 4 m,t = 2 s, u = 0, F = ?$

We can find acceleration by using below formula

$s = ut + \frac{1}{2} {at}^{2} \Rightarrow 4 = \frac{1}{2} a {(2)}^{2}$

$a = 2 {m/s}^{2}$

$F = ma = 0.2 \times 2$

$F = 0.4 N$

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A force acting on a particle of mass 200 g displaces it through 400 cm in 2 seconds. If the initial velocity of the particle is zero, then the magnitude of the force is