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A force acts for $0.1 s$ on a body of mass $1.2 kg$ initially at rest. The force then ceases to act, and the body moves through $2 m$ in the next one second. The magnitude of the force will be

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26 N

24 N

14 N

45 N

answer is B.

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Detailed Solution

A force acts for

0.1 s

on a body of mass

1.2 kg

initially at rest. The force then ceases to act, and the body moves through

2 m

in the next one second. The magnitude of the force will be

24 N

.
Initial motion of body

(u) = 0 m / s

Final motion of the body

v = s / t

v = 2 / 1

= 2 m / s

From the 1st equation of motion we have

u = v + at

= > a = \frac{2 - 0}{0.1}

= > a = 20 m / s^{2}

Now, from the relation of Newton’s second law

= > F = ma

= > F = 1.2 \times 20

= 24 N

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