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A force acts for $10 s$ on a stationary body of mass, $100 kg$ after which it means it ceases it act. The body moves through a distance of $100 m$ in the next $5 seconds$ . The magnitude of the force will be

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200 N

300 N

400 N

250 N

answer is A.

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Detailed Solution

A force acts for

10 s

on a stationary body of mass,

100 kg

after which it means it ceases it act. The body moves through a distance of

100 m

in the next

5 seconds

. The Magnitude of the force will be

200 N .

Given that,
Mass of the body

(m) = 100 kg

Distance

= 100 m

Time taken

= 10 seconds

Initial velocity = 0 m/s
From the equation of

= > s = ut + \frac{1}{2} a t^{2}

= > 100 = 0 \times 5 + ½ \times a \times 100

On solving the equation, we have,
Acceleration,

a = 2 m / s^{2}

Magnitude of the force F = mass × acceleration
Force

F = 100 \times 2

Force

F = 200 N

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