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Q.

A force acts for 20 s on a body of mass 20 kg starting from rest, after which the force ceases and then body describes 50 m in the next 10 s. The value of force will be:

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a

20 N

b

5 N

c

40 N

d

10 N

answer is A.

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Detailed Solution

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Let say applied force is F then
Impulse, J=FΔt=muu=F×2020=F
As s=ut50=F×10F=5N

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