A force acts on a body of mass $3 kg$ causing its speed to increase from $4 m / s to 5 m / s$ . Work done will be ____.

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Detailed Solution

A force acts on a body of mass

3 kg

causing its speed to increase from

4 m / s to 5 m / s

. Work done will be

13.5 Joule

.
According to the work-energy conversion theorem;
Work done by the force = Change in Kinetic energy
Work done by the force

= \frac{1}{2} \times m \times (v^{2} - u^{2})

Given:

u (initial velocity) = 4 m / s

v (final velocity) = 5 m / s

m = 3 kg

Work done by the force

= \frac{1}{2} \times m \times (v^{2} - u^{2})

Work done by the force

= \frac{1}{2} \times 3 \times (5^{2} - 4^{2})

Work done by the force

= \frac{1}{2} \times 3 \times (25 - 16)

Work done by the force

= \frac{1}{2} \times 3 \times 9

= 13.5 Joule

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