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A force $\vec{F} = (2 i - 3 k) N$ act on a particle, whose position vector about origin is $\vec{r} = (0.5 j - 2 k) m$ . The torque $\vec{τ}$ acting on a particle with respect to a point (2,0,-3) m will be

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$(3 i + 6 j - k) Nm$

$(- 20 i + 4 j + k) Nm$

$(- 1.5 i - 4 j - k) Nm$

$(- 3 i - 4.5 j - k) Nm$

answer is A.

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Detailed Solution

$\vec{τ} = (\vec{r_{2}} - \vec{r_{1}}) \times \vec{F}$

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