Q.

A force F=2i^+bj^+k^ is applied on a particle and it undergoes a displacement i^2j^k^. What will be the value of b, if work done on the particle is zero.

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a

0

b

2

c

12

d

13

answer is B.

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Detailed Solution

The dot product of F and d is:

Fd=(2)(1)+(b)(2)+(1)(1)=1-2b

Set Fd=0 (since the work done is zero):

12b=01 - 2b = 0

b=12b = \frac{1}{2}

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A force F→=2i^+bj^+k^ is applied on a particle and it undergoes a displacement i^−2j^−k^. What will be the value of b, if work done on the particle is zero.