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Q.

A force F¯=(5i^3j^+2k^)N  moves a particle from  r¯1=(2i^+7j^+4k^)m    to   r¯2=(5i^+2j^+8k^)m. The work done by the force is (in J)

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a

28

b

34

c

24

d

38

answer is B.

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Detailed Solution

  W=F¯.S¯        where       S¯=r¯2r¯1

W=(5i^-3j^+2k^)(3i^-5j^+4k^)=38J

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