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A force $F$ acts between sodium and chlorine ions of salt (sodium chloride) when put $1 c m$ apart in air. When a piece of salt is put in water electrical force acting between sodium and chlorine ions $1 c m$ apart is (The permittivity of air $ε_{0}$ and dielectric constant of water $K$ ).

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$\frac{F ε_{0}}{K}$

$\frac{F}{K ε_{0}}$

$\frac{F K}{ε_{0}}$

$\frac{F}{K}$

answer is A.

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Detailed Solution

When put 1 cm apart in air, the force between $N a$ and $C l$ ions = $F$ . When put in water, the force between $N a$ and $C l$ ions $= \frac{F}{K}$

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