A force f1 is applied on a ball of mass 3kg moving with acceleration 5ms-2. Another force f2 is applied on a ball of mass 4kg with an acceleration 4ms-2. Find out the relationship between force f1 and f2.

M1= 3kg M2=4kg a1 = 5ms-2 a2= 4ms-2 f1=? f2=? we know that F= m×a f1=3×5=15N f2=4×4=16N so from this we can say that f2>f1

A force f1 is applied on a ball of mass 3kg moving with acceleration 5ms-2. Another force f2 is applied on a ball of mass 4kg with an acceleration 4ms-2. Find out the relationship between force f1 and f2.

M1= 3kg M2=4kg a1 = 5ms-2 a2= 4ms-2 f1=? f2=? we know that F= m×a f1=3×5=15N f2=4×4=16N so from this we can say that f2>f1

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A force f₁ is applied on a ball of mass 3kg moving with acceleration $5 {ms}^{- 2}$ . Another force f₂ is applied on a ball of mass 4kg with an acceleration $4 {ms}^{- 2}$ . Find out the relationship between force $f_{1}$ and $f_{2}$ .

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$f_{2} \geq f_{1}$

$f_{1} \geq f_{2}$

$f_{1} = f_{2}$

$f_{2} > f_{1}$

answer is D.

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$M_{1} = 3 kg M_{2} = 4 kg a_{1} = 5 {ms}^{- 2} a_{2} = 4 {ms}^{- 2} f_{1} = ? f_{2} = ? we know that F = m \times a f_{1} = 3 \times 5 = 15 N f_{2} = 4 \times 4 = 16 N so from this we can say that f_{2} > f_{1}$

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A force f1 is applied on a ball of mass 3kg moving with acceleration 5ms-2. Another force f2 is applied on a ball of mass 4kg with an acceleration 4ms-2. Find out the relationship between force f1 and f2.

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A force f₁ is applied on a ball of mass 3kg moving with acceleration $5 {ms}^{- 2}$ . Another force f₂ is applied on a ball of mass 4kg with an acceleration $4 {ms}^{- 2}$ . Find out the relationship between force $f_{1}$ and $f_{2}$ .