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A force is applied on a body of mass 0.9 kg that is at rest. The force is applied for a duration of 5s and as a result, the body covers a distance of 250 m. Find the magnitude of the force.

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9 N

18 N

27 N

46 N

answer is B.

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Detailed Solution

Using s = ut + $\frac{1}{2} a t^{2} we can write 250 = \frac{1}{2} \times a \times 5^{2}$

a = 20 m/s² F = ma = 0.9 x 20 = 18N

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