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Q.

A force of 10 N acts on a body towards the east. The work done by the force while the body moves through 1m in the east-north direction

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a

1052 J

b

\frac{10}{\sqrt{2}} J

c

– 10 J

d

- \frac{10}{\sqrt{2}} J

answer is B.

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Detailed Solution

W = FS

$F = 10N, S = 1m, θ = 45°$

$W = FScos θ$

$= 10 \times \frac{1}{\sqrt{2}} = \frac{10}{\sqrt{2}} J$

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