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Q.

A force of 10N is exerted on the handle of a door the door can be just opened. The handle is at a distance of 50cm from the hing. Then the torque = ____ N.m

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answer is 5.

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Detailed Solution

$τ = rF . \sin θ; θ = 90^{\circ}$

$\Rightarrow τ = 50 \times 10^{- 2} \times 10 \times \sin 90^{o} = 5 N . m$

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A force of 10N is exerted on the handle of a door the door can be just opened. The handle is at a distance of 50cm from the hing. Then the torque = ____ N.m