Q.

A force of 10N is exerted on the handle of a door the door can be just opened. The handle is at a distance of 50cm from the hing. Then the torque =  ____ N.m 

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answer is 5.

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Detailed Solution

τ=rF.sin θ;  θ=90

τ=50×10-2×10×sin90o=5N.m

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