A force of 12 N displaces an object by 12 m in the direction of the force. Find the work done?

Work done is given by:

Work(W) = Force(F) x Displacement(s)

$\mathrm{W} = \mathrm{Fscos\theta }$

Where θ is the angle between force and displacement.

From the question we have,
Force(F) = 12 N
Displacement(s) = 12 m
θ = 0 ° (Force and displacement happening in the same direction)

So, the work done is,
$\mathrm{W} = \mathrm{F} \times \mathrm{dcos\theta }$ 
$\mathrm{W}= 12\times 12\times \cos 0 °$
$\mathrm{W} = 144\times 1 = 144 \mathrm{J}$

Therefore, the work done will be 144 J.