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Q.

A force of 32 N acts on a particle in vertically upward direction and the particle is displaced through 2m in vertically downward direction. The work done by the force during displacement is

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a

64 J

b

16 J

c

64 J

d

32 J

answer is C.

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Detailed Solution

To calculate the work done by a force, we use the formula:

Work Done (W) = F × d × cos θ,

where:

  • F is the force applied,
  • d is the displacement,
  • θ is the angle between the force and the displacement direction.

Given:

  • Force (F) = 32 N (vertically upward),
  • Displacement (d) = 2 m (vertically downward),
  • Angle (θ) = 180° (force is upward, displacement is downward, so they are in opposite directions).

The cosine of 180° is -1, so the work done is:

W = F × d × cos θ

W = 32 × 2 × (-1)

W = -64 J

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