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Q.

A force of 60 N is applied on a nail, where tip has a area of cross-section of $0.001 {cm}^{2}$ , then the pressure on the tip is

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a

6 \times 10^{10} pa

b

6 \times 10^{4} pa

c

6 \times 10^{6} pa

d

6 \times 10^{8} pa

answer is A.

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Detailed Solution

F = 60 N,A = 0.001 {cm}^{2}

$A = 1 \times 10^{- 3} {cm}^{2} = 1 \times 10^{- 7} m^{2}$

$∴ P = \frac{F}{A} = \frac{60}{10^{- 7}} = 6 \times 10^{8} Pa$

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