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Q.

A force of 6.4 N stretches a vertical spring by 0. I m. The mass that must be suspended from the spring so that it oscillates with a time period of $\frac{π}{4}$ second.

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a

10 kg

b

$\frac{4}{π} kg$

c

$\frac{π}{4} kg$

d

1 kg

answer is C.

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Detailed Solution

Spring constant $K = \frac{6.4}{0.1} = 64 N / m$

Now T = $2 π \sqrt{\frac{m}{k}}$

or $\frac{π}{4} = 2 π \sqrt{\frac{m}{64}} ∴ m = 1 kg$

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