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A force of $7 N$ acts on an object. The displacement is, say $8 m$ , in the direction of the force. Let us take it that the force acts on the object throughout the displacement. What is the work done in this case?

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56 N

56 J

64 N

64 J

answer is B.

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Detailed Solution

The work done in this case is

56 J

Given data

Force acting on the body

(F) = 7 N

Displacement of the body

(S) = 8 m

Formula used

W = FScosθ

where

W

stands for work done,

F

for the force acting on the body,

S

for displacement, and

θ

for the angle formed by the force's direction and the displacement vector.
Determine the amount of work completed.
Considering that the body is moving in the direction of the applied force,

= 0

.
Now, when we enter the specified values into the formula, we obtain

W = 7 \times 8 \times \cos (0 °)

W = 7 \times 8 \times 1

W = 56 J

Thus, the work done in this case will be

56 J

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