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Q.

A force of Fk^ acts on origin, then the torque about the point (1,1) is :

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a

F(i^j^)

b

-F(i^j^)

c

F(i^+j^)

d

F(j^i^)

answer is D.

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Detailed Solution

τ=r×F Force acts on origin so r is position vector of origin wrt. (1,1) so

r=i^+j^,F=Fk^

τ=(i^+j^)×(Fk^)=Fi^+Fj^

 

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