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Q.

A force (5i^+7j^3k^)N acts on a particle at position (i^+j^k^)m. Find torque of this force on the particle about origin

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a

(4i^+2j^+2k^)Nm

b

(4i^2j^+2k^)Nm

c

(4i^+2j^2k^)Nm

d

(10i^8j^+12k^)Nm

answer is B.

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Detailed Solution

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τ=r×F=i^j^k^111573=i^(3+7)j^(3+5)+k^(75)=(4i^2j^+2k^)Nm

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