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A force $\vec{F} = (2 \hat{i} + 2 \hat{j} + 2 \hat{k}) N$ acts on a particle which is constrained to move in the XOY plane along the line x = y. If the particle moves $5 \sqrt{2} m$ , the work done by force in joule is

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$25 \sqrt{2}$

$5 \sqrt{58}$

answer is C.

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Detailed Solution

$\vec{S} = 5 \hat{i} + 5 \hat{j}, W = \vec{F} . \vec{S}$

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