A fraction becomes 13 when 1 is subtracted from the numerator and it becomes 14 when 8 is added to its denominator.Form equation to find the fraction.( Assume 'x' as the numerator and 'y' as the denominator. )

x - 1 y - 1 = 1 3 , x + 8 y + 8 = 1 4

x - 1 y + 8 = 1 3 , x + 1 y + 8 = 1 4

x - 1 y - 8 = 1 3 , x + 1 y + 8 = 1 4

Book Online Demo

Check Your IQ

Try Test

Courses

A fraction becomes $\frac{1}{3}$ when 1 is subtracted from the numerator and it becomes $\frac{1}{4}$ when 8 is added to its denominator.
Form equation to find the fraction.
( Assume 'x' as the numerator and 'y' as the denominator. )

see full answer

21% of IItians & 23% of AIIMS delhi doctors are from Sri Chaitanya institute !!

An Intiative by Sri Chaitanya

$\frac{x - 1}{y} = \frac{1}{3}, \frac{x}{y + 8} = \frac{1}{4}$

$\frac{x - 1}{y - 1} = \frac{1}{3}, \frac{x + 8}{y + 8} = \frac{1}{4}$

$\frac{x - 1}{y + 8} = \frac{1}{3}, \frac{x + 1}{y + 8} = \frac{1}{4}$

$\frac{x - 1}{y - 8} = \frac{1}{3}, \frac{x + 1}{y + 8} = \frac{1}{4}$

answer is A.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Let 'x' be the numerator and 'y' be the denominator.

As per condition 1,

$\frac{x - 1}{y} = \frac{1}{3}$ -- (1)

As per condition 2,

$\frac{x}{y + 8} = \frac{1}{4}$ -- (2)

Watch 3-min video & get full concept clarity