A fractional change in volume of oil is 1 percent when a pressure of 2×107Nm−2 is applied. Calculate the bulk modulus and its compressibility

5 × 10 9 N m − 2 , 2 × 10 − 10 m 2 N − 1

A fractional change in volume of oil is 1 percent when a pressure of 2×107Nm−2 is applied. Calculate the bulk modulus and its compressibility

5 × 10 9 N m − 2 , 2 × 10 − 10 m 2 N − 1

2 × 10 9 N m − 2 , 5 × 10 − 9 m 2 N − 1

3 × 10 8 N m − 2 , 0.33 × 10 − 9 m 2 N − 1

5 × 10 9 N m − 2 , 2 × 10 − 10 m 2 N − 1

2 × 10 9 N m − 2 , 5 × 10 − 10 m 2 N − 1

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A fractional change in volume of oil is 1 percent when a pressure of $2 \times 10^{7} N m^{- 2}$ is applied. Calculate the bulk modulus and its compressibility

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$2 \times 10^{9} N m^{- 2}, 5 \times 10^{- 9} m^{2} N^{- 1}$

$3 \times 10^{8} N m^{- 2}, 0.33 \times 10^{- 9} m^{2} N^{- 1}$

$5 \times 10^{9} N m^{- 2}, 2 \times 10^{- 10} m^{2} N^{- 1}$

$2 \times 10^{9} N m^{- 2}, 5 \times 10^{- 10} m^{2} N^{- 1}$

answer is C.

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Detailed Solution

$K = \frac{- P}{(\frac{Δ V}{V})} = \frac{2 \times 10^{7}}{(\frac{1}{100})} = 2 \times 10^{9} N / m^{2}$

$C = \frac{1}{k} = \frac{1}{2 \times 10^{9}} = 0.5 \times 10^{- 9}$

$= 5 \times 10^{- 10} m^{2} / N$

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