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Q.

A frequency distribution table regarding the blood groups of 30 students of a class is prepared. Use this table to determine the probability that a student of this class, selected at random, has blood group AB.

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a

\frac{1}{10}

b

\frac{3}{10}

c

\frac{1}{30}

d

\frac{7}{30}

answer is C.

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Detailed Solution

It is given a table,
Question Image

Question Image

Probability of any event,P(E)

= \frac{n (E)}{n (S)}

Number of favourable outcomes = n(E); Number of total outcomes = n(S); Probability of event = P(E)
It is given that the total number of students is 30 so the total number of outcomes = n(S)= 30
The favourable outcome is selecting a student with blood group AB.
In the table it is given that number of students with blood group AB = 3= n(E)
Probability of event occurring will be,

\Rightarrow P (E) = \frac{n (E)}{n (S)}

\Rightarrow P (E) = \frac{3}{30}

\Rightarrow P (E) = \frac{1}{10}

Hence option (3) is correct.

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