A frustum of a cone has radii of 15 cm and 30 cm, and the height is 10 cm. Find the volume of the frustum.

Given: Radius of the lower base of the frustum (r₁) = 15 cm

Radius of the upper base of the frustum (r₂) = 30 cm

Height of frustum (h) = 10 cm
∴ Volume of the frustum = $\frac{1}{3}$πh(r₁² + r₂² + r₁r₂)
= $\frac{1}{3}$ × 3.14 × 10 (15² + 30² + 15×30)

= $\frac{1}{3}$ × 3.14 × 10 (225 + 900 + 450)

= $\frac{1}{3}$ × 3.14 × 10 × 1575
= 16485 cm³

Therefore, the volume of the frustum is 16485 cm³.