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Q.

A fuel cell uses CH4g  and  forms CO32− at the anode. It is used to power a car with 80 Amp for 1 hour. How many liters of CH4g (at STP) would be required? Vm=22.7  L/mol&F=96500  Coulumbs . Assume 100% efficiency.

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a

4.04 L

b

8.47 L

c

8.05 L

d

4.18 L

answer is B.

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Detailed Solution

CH4+10  OH−→  CO32−+7 H2O+8 e−

No. of  Faradays  required=18×80×3600×196500

VCH4=18×80×3600×196500×22.7  L=8.47L

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