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Q.

A fully charged capacitor C with initial charge Q is connected to a coil of self inductances L at t = 0. The time at which the energy is stored equally between the, electric and the magnetic fields is :

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a

πLC

b

2πLC

c

LC

d

π4LC

answer is B.

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Detailed Solution

energy across the capacitor becomes half when energy across inductor and capacitor are equal i.e Q24C

Q24C= Q2cos2ωt2C 12= cosωt 1LCt=π4 t= π4LC 

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