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A fully charged capacitor has a capacitance ‘C’. It is discharged through a small coil of resistance wire embedded in a thermally insulated block of specific heat capacity ‘s’ and mass ‘m’. If the temperature of the block is raised by $' Δ T'$ , then the potential difference ‘V’ across the capacitor is

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$\frac{m C Δ T}{s}$

$\sqrt{\frac{2 m s Δ T}{C}}$

$\sqrt{\frac{2 m C Δ T}{s}}$

$\frac{2 m C Δ T}{s}$

answer is B.

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Detailed Solution

By law of conservation of Energy

$\begin{array}{l} \frac{1}{2} C V^{2} = M S Δ t \\ V = \sqrt{\frac{2 m s Δ t}{C}} \end{array}$

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