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Q.

A function f from the set of natural numbers to integers defined by f(n)=n12, when n is odd n2, when n is even is

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a

neither one -one nor onto

b

one-one but not onto

c

onto but not one-one

d

one-one and onto both.

answer is D.

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Detailed Solution

We have f : N 

If x and y are two even natural numbers, then f(x)=f(y)x2=y2x=y

Again if x and y are two odd natural numbers then f(x)=f(y)x-12=y-12x=y

 f is one-one .

 Also each negative integer is an image of even natural number and each positive integer is an image of odd natural number. 

 f is onto.

Hence f is one one and onto both.

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