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Q.

A function f from the set of natural numbers to integers defined by f(n)=n12,   when  n  is  oddn2,   when  n  is  even     is  

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a

Neither one – one nor onto

b

one-one but not onto

c

Onto but not one-one

d

one-one and onto both

answer is D.

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Detailed Solution

Let  x1  and  x2  be   any  two  elements  in  the  domain  (N).Case1:  When  bothx1  and  x2are  even.Let  f(x1)=f(x2)x12=x22x1=x2x1=x2Case  2:  When  bothx1  and  x2are  odd.Letf(x1)=f(x2)x112=x212x1=x2Case  3:  When  x1be  even  and  x2be  odd.Then,  f(x1)=x12   and  f(x2)=x212Then   clearly,  x1x2f(x1)f(x2)From  all   the  cases,we  can  say  that,f  is  oneone.Codomain  of  f=Range  of  ff  is  onto.

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