A furniture trader deals in only items-chairs and tables. He has Rs. 50, 000 to invest and a space to store at most 35 times. A chair costs him Rs. 1,000 and a table costs him Rs. 2, 000. The trader earns a profit of Rs. 150 and Rs. 250 on a chair and table, respectively. Formulate the above problem as an LPP to maximizes the profit and solve it graphically.

Let consider the number of chairs as x,
Number of tables as y,
From the data,
Maximize the profit: P=150x+250y
According to the data,
$\begin{array}{l}\mathrm{x}+\mathrm{y}\le 35\\ 1000\mathrm{x}+2000\mathrm{y}\le 50000\\ \therefore \mathrm{x}+2\mathrm{y}\le 50\end{array}$
Where, $\mathrm{x}\ge 0,\mathrm{y}\ge 0$
From the both equation $\mathrm{x}+\mathrm{y}=35$ and $\mathrm{x}+2\mathrm{y}=50$ we will get the intersection point B(20, 15). Which we can see in the below graph,

We can see that given problem has feasible solution,
Therefore, the corner points of the feasible region are:
O(0, 0), A(0, 25), B(20, 15) and C(35, 0)
For maximum value of profit check at corner point,
Value of profit P at (0, 25) = 150(0)+250(25)=Rs. 6250
Similarly, for (20, 15) and (35, 0) respectively Rs. 6750 and Rs. 5250.
Therefore, the maximum value of profit P is Rs. 6750 at x=number of chairs=20 and y= number of tables=15.