A(g) is 100% converted into ‘B’ according to reaction A(g)⇌3B(g) value of Dd at this point is

X=D−dd(n−1) Here n=3X=D−d2d⇒2X=D−ddDd=2X+1X = 1When Dd=2(1)+1= 3

A(g) is 100% converted into ‘B’ according to reaction A(g)⇌3B(g) value of Dd at this point is

X=D−dd(n−1) Here n=3X=D−d2d⇒2X=D−ddDd=2X+1X = 1When Dd=2(1)+1= 3

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A_(g) is 100% converted into ‘B’ according to reaction $A_{(g)} ⇌ 3 B_{(g)}$ value of $(\frac{D}{d})$ at this point is

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$X = \frac{D - d}{d (n - 1)}$ Here n=3
$\begin{array}{l} X = \frac{D - d}{2 d} \Rightarrow 2 X = \frac{D - d}{d} \\ \frac{D}{d} = 2 X + 1 \end{array}$
X = 1
When $\frac{D}{d} = 2 (1) + 1$
= 3

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A(g) is 100% converted into ‘B’ according to reaction A(g)⇌3B(g) value of Dd at this point is

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A_(g) is 100% converted into ‘B’ according to reaction $A_{(g)} ⇌ 3 B_{(g)}$ value of $(\frac{D}{d})$ at this point is