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A Galilean telescope of length 32 cm produces image at far point with objective of focal length 40 cm. Then

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focal length of eye piece is 8 cm

magnification produced is 5

focal length of eye piece is 5 cm

magnification produced is 8

answer is A, C.

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Detailed Solution

$L = f_{o} - f_{e} = 32 cm$ and $f_{0} = 40 cm$

$\Rightarrow f_{e} = 8 cm, MP = \frac{f_{o}}{f_{e}} = \frac{40}{8} = 5$

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