A galvanic at 298 K: ${\mathrm{MnO}}_4^{-}+8{\mathrm{H}}^{+}+5{\mathrm{Fe}}^{2+}\to {\mathrm{Mn}}^{2+}+5{\mathrm{Fe}}^{3+}+4{\mathrm{H}}_2\mathrm{O}$

Given: $E^{\circ }\left({\mathrm{MnO}}_4^{-},{\mathrm{Mn}}^{2+},{\mathrm{H}}^{+}\mid \mathrm{Pt}\right)=1.51\mathrm{V}\text{ and }{E}^{\circ }\left({\mathrm{Fe}}^{3+},{\mathrm{Fe}}^{2+}\mid \mathrm{Pt}\right)=0.77\mathrm{V}$

The standard cell potential is

$E_{\text{cell }}^{\circ }=1.51\mathrm{V}-0.77\mathrm{V}=0.74\mathrm{V}$

The potential difference between the cathode and anode is the standard cell potential. Cell Potentials can be viewed for further details. At 298 K, 1 atm, and using 1 M solutions, the standard potentials are all measured.