A Galvanic cell comprises of two half cells, ${\mathrm{E}}_{{\mathrm{Mg}}^{2+}/\mathrm{Mg}}^0=-2.37\mathrm{V}$ and  ${\mathrm{E}}_{{\mathrm{Al}}^{3+}/\mathrm{Al}}^0=-1.66\mathrm{V}$ Oxidation takes place at __________electrode and cell emf is ___________

Magnesium electrode, 0.71V

The electrode with maximum negative potential or least positive potential will be the Anode, where Oxidation takes place. ${\mathrm{E}}_{\mathrm{cell}}={\mathrm{E}}_{\mathrm{cathode}}-{\mathrm{E}}_{\mathrm{anode}}=-1.66-(-2.37)=0.71\mathrm{V}$