A galvanometer gives full scale deflection with 0.006A current. By connecting it to a 4990 $Ω$ resistance, it can be converted into a voltmeter of range 0-30V. If connected to a 2n/249 $Ω$ resistance, it becomes an ammeter of range 0-1.5A. The value of n is

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answer is 5.

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Detailed Solution

$V = i_{g} (G + R)$

$\begin{array}{l} 30 = 0.006 (G + 4990) \\ \Rightarrow G = 10 Ω \\ S = \frac{G i g}{i - i g} \\ \frac{2 n}{249} = \frac{0.006 \times 10}{1.5 - 0.006} \end{array}$

$n = 5$

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