A galvanometer has a current range of 15mA and voltage range of 750mV. To convert this galvanometer into an ammeter of range 25A, the shunt resistance required is nearly

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0.02Ω

0.2 Ω

0.03Ω

0.5Ω

answer is C.

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Detailed Solution

$\begin{array}{l} G = \frac{750 \times 10^{- 3}}{15 \times 10^{- 3}} = 50 Ω; S = \frac{G}{\frac{i}{i_{g}} - 1} \\ S = \frac{50}{\frac{25}{15 \times 10^{- 3}} - 1} = \frac{50}{\frac{5000}{3} - 1} ≃ \frac{150}{5000} = 0 .034 Ω \end{array}$

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