A galvanometer having a resistance of 50 Ω, gives a full scale deflection for a current of 0.05 A. The length in metre of a resistance wire of area of cross section 2.97 × 10–2 cm2 that can be used to convert the galvanometer into an ammeter which can read a maximum of 5 A current is (specific resistance of the wire = 5×10−7 Ωm)

0.05×50= (5-0.05)5×10-7L2.97×10-2×10-4 L = 3m

A galvanometer having a resistance of 50 Ω, gives a full scale deflection for a current of 0.05 A. The length in metre of a resistance wire of area of cross section 2.97 × 10–2 cm2 that can be used to convert the galvanometer into an ammeter which can read a maximum of 5 A current is (specific resistance of the wire = 5×10−7 Ωm)

0.05×50= (5-0.05)5×10-7L2.97×10-2×10-4 L = 3m

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A galvanometer having a resistance of 50 Ω, gives a full scale deflection for a current of 0.05 A. The length in metre of a resistance wire of area of cross section 2.97 × 10^–2 cm² that can be used to convert the galvanometer into an ammeter which can read a maximum of 5 A current is (specific resistance of the wire = $5 \times 10^{- 7} Ωm)$

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$0.05 \times 50 = \frac{(5 - 0.05) 5 \times 10^{- 7} L}{2.97 \times 10^{- 2} \times 10^{- 4}} L = 3 m$

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