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Q.

A galvanometer is connected in series with a wire ‘AB’ through which a current ‘I0’ is flowing. When this galvanometer is shunted with a 4Ω resistance, the deflection is reduced to one-fifth. If the galvanometer is further shunted with a 2Ω wire, current flowing in galvanometer is (given main current (I0) remains same)

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a

5I0/13

b

I0/13

c

I0/5

d

I0/8

answer is A.

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Detailed Solution

In parallel, current distributes in inverse ratio of resistance

Now IGIR=RG=(4/3)16=112

IG=113I0

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