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A galvanometer of resistance 10 Ω gives full-scale deflection when 1 mA current passes through it. The resistance required to convert it into a voltmeter reading up to 2.5 V is

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24900 Ω

249 Ω

2490 Ω

24.9 Ω

answer is C.

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Detailed Solution

Let R be the resistance to be connected in series with the galvanometer of resistance G in order to convert it into a voltmeter reading up to 2.5 V. Then the current through the galvanometer is

$I_{g} = \frac{2.5}{R + G}$

$P u t t i n g I_{g} = 1 m A = 1 x 10^{- 3} A a n d$

$G = 10 Ω, w e g e t R = 2490 Ω .$

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