A galvanometer of resistance 150 ohm is shunted such that only 1/11 of the main current flows through the galvanometer. The resistance of the shunt is, (in ohm)

The equipment used to measure the current in an electric circuit is called a galvanometer. By connecting a low resistance shunt in parallel with the galvanometer, an ammeter can be formed from a galvanometer.

$G=150\Omega$

We know that the value of shunt is,

$S =\frac{I_{g}G}{I-I_g}\_\_\_\_\_\_\_\_\_\_\left(1\right)$

Now we have,
 $I_g=\frac{1}{11}\times I=\frac{I}{11}$
substituting the value in equation in (1) 
$S=\frac{{\displaystyle \frac{I}{11}\times 150}}{I-{\displaystyle \frac{I}{11}}}=\frac{{\displaystyle \frac{150I}{11}}}{{\displaystyle \frac{11I-I}{11}}}=\frac{150I}{10I}=15\Omega$
So the resistance of the shunt is 15 Ω.