A galvanometer of resistance $20 Ω$ shows a deflection of 10 divisions when a current of 1 mA is passed through it. If a shunt of $4 Ω$ is connected and there are 50 divisions on the scale, the range of the galvanometer is :

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1 mA

30 mA

3 mA

10 mA

answer is D.

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Detailed Solution

$S = \frac{G}{n - 1} and$

$n = \frac{i}{ig}$

$\begin{array}{l} I_{g} = \frac{1 \times 50}{10} = 5 mA \\ ∴ \frac{I_{g}}{I} = \frac{S}{S + G} \\ \Rightarrow I = (\frac{S + G}{S}) I_{g} \\ Or I = (\frac{4 + 20}{4}) 5 mA \\ = 30 mA \end{array}$

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