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Q.

A galvanometer of resistance 30 ohm is converted into an ammeter of range 2.8 A by connecting a shunt resistance 12 ohm to the galvanometer. What can be the range of ammeter if a resistance 6 ohm is connected in parallel to the shunt 12 ohm?

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a

3.6 A

b

4.8 A

c

5.2 A

d

6.8 A

answer is D.

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Detailed Solution

$\begin{array}{l} \frac{I}{I_{g}} = \frac{S + G}{S} \\ \Rightarrow \frac{I_{1}}{I_{2}} = \frac{S_{1} + G}{S_{2} + G} \times \frac{S_{2}}{S_{1}} \\ S_{1} = 12 Ω and \\ S_{2} = \frac{12 \times 6}{12 + 6} = 4 Ω \\ \frac{2 .8}{I_{2}} = \frac{42}{34} \times \frac{4}{12} \\ I_{2} = 6 .8 A \end{array}$

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