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Q.

A galvanometer of resistance 100 Ω gives a full scale deflection for current of 10-5A. To convert it into a ammeter capable of measuring upto 1 A, we should connect a resistance of 

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a

100 Ω in series

b

1Ω in parallel 

c

10-3Ω in parallel

d

105Ω in series 

answer is B.

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Detailed Solution

Here, Rg=100Ω; Ig=10-5A;I=1 A;S=?

S=IgRgI-Ig=10-5×1001-10-5=10-3Ω in parallel

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