A game consists of tossing a one rupee coin 3 times and noting the outcome each time. Ramesh will win the game if all the tosses show the same result, (i.e either all three heads or all three tails) and loses the game otherwise. Find the probability that Ramesh will lose the game.

We use the basic formula of favorable outcomes to solve the problem. 

Total possible outcomes are = {𝐻𝐻𝐻, 𝑇𝑇𝑇, 𝐻𝑇𝐻, 𝐻𝐻𝑇, 𝑇𝐻𝐻, 𝑇𝐻𝑇, 𝑇𝑇𝐻, 𝐻𝑇𝑇} = 8

The number of possible outcomes to get three heads or three tails is 2.

The probability that Ramesh will win the game = $=\frac{\text{ Number of possible outcomes }}{\text{ Total number of favourable outcomes }}$

$\begin{array}{r}=\frac{2}{8}\\ =\frac{1}{4}\end{array}$

The probability that Ramesh will lose the game $=1-\frac{1}{4}$

Hence, the probability that Ramesh will lose the game is $\frac{3}{4}$.