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A game of chance consists of an arrow which comes to rest pointing at one of the regions 1,2 or 3. O is the centre of the circle, $O C ⊥ A B$ then find the probability that the arrow is resting on 3.

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12

14

23

35

answer is A.

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Detailed Solution

Given, a game of chance consists of an arrow which comes to rest pointing at one of the regions 1,2 or 3. O is the centre of the circle,

.
The probability of an event to be occurred is the division of the number of favourable outcomes by the total number of outcomes that is,

Probability of an event = Number of favourable outcomes Total number of outcomes

Finding the possible outcomes of an arrow resting at any place.
The possible outcomes of the arrow resting at 3 is

180 °

The total number of possible outcomes is

360 °

Find the probability that the arrow rests at 3.
By dividing the number of favourable outcomes by the total number of possible outcomes.

Probability = Number of favourable outcomes Total number of possible outcomes = 180360 = 12

Thus, the probability of the arrow resting at 3 is

12

.
Hence, the correct option is 1.

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