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A gas absorbs 250 J of heat and expands from 1 litre to 10 litre at constant temperature against external pressure of 0.5 atm. The values of q, w and Δ E will be respectively.

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250J, 455J and 710J

250J, – 455J and -205J

-250J, -455J and -205J

-250J, 455J and 205J

answer is B.

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Detailed Solution

W = -PΔV = - 0.5(10-1) =-4.5 lit-atm
= 4.5x101.3 = -455J
q = +250J
ΔE = q+W = 250 - 455
= -205J

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